计算:lim[1/x+1/(x^2)ln(1-x)]
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计算:lim[1/x+1/(x^2)ln(1-x)]计算:lim[1/x+1/(x^2)ln(1-x)]计算:lim[1/x+1/(x^2)ln(1-x)]通分,得:前面有一个负号,我忘写了lim[1
计算:lim[1/x+1/(x^2)ln(1-x)]
计算:lim[1/x+1/(x^2)ln(1-x)]
计算:lim[1/x+1/(x^2)ln(1-x)]
通分,得:
前面有一个负号,我忘写了
lim
= -1/2
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