化简：2sin(πx/8+π/4)+sin(-πx/8+π/4)=

傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si 化简：2sin(πx/8+π/4)+sin(-πx/8+π/4)= 根号2sin(x+π/4)化简 2sin(x+π/4)sin(x-π/4)=? 设f(x)=4cos(ωx-π/6)sinωx-cos(2ωx+π),其中ω>0,求函数y=f(x)的值域,请看问题补充f（x）=4cos（ωx-π/6）sinωx-cos（2ωx+π） =4(coswxcosπ/6+sinwxsinπ6)sinwx+cos2wx =2√3sinwxcoswx+2sin²wx+cos2wx =√3si sin^2(π/4 +x) 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 化简 sin²x+sin²(x+2π/3)+sin²(x-2π/3) 根号2sin(πx/8+π/4)+根号2sin(πx/8+3π/4)化简 f(x)=cos(2x-x/3)+2sin(x-π/4)sin(x+π/4)sin(x+π/4)化简. sin(x+π/4) 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). 化简sin（2π+x）cos（π-x）sin（π-x）/cos（x-π）sin（-π-x）sin（π+x） f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) sin^8X+cos^8X+4sin^2Xcos^2x-2sin^4xcos^4X(化简） 化简sin^4x-sin^2x+cos^2x 化简:sin^4 x-sin^2 x+cos^2 x