log 2 X =3/2 怎么算出x的值来?

log 2 X =3/2 怎么算出x的值来? 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 [log(x)(25)]^2 就是对数函数外的平方怎么算?2log(x)(25)-3log(25)(x)=1 2 log(3x)= log 4 +log(6-x)怎么求...急 log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 2log(x)(25)-3log(25)(x)=1怎么解X啊.急 2log∨6x=1-log∨6 3,则x的值是什么 log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) 已知log(2)X,log(2)|X|,log(2)(-X),-log(2)X的图像怎么画?不过（3） 就是将log(2)X的x换成-x，就是关于轴对称。关于哪个轴对称啊? 怎么画出y=log|x+2|和y=log|x|的图像 于是f(x)=9[log(4,x)]^2-[log(2,x)]^2=9[1/2*log(2,x)]^2-[log(2,x)]^2=5/4*[log(2,x)]^2 怎么得的? 已知log(a)x^2>log(a)2x+3,求x的取值范围 （高一）若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{log(√2)[(√x)/2]}的最大值和最小若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{log(√2)[(√x)/2]}的最大值和最小值,并求此时x的值.rt log（x+5）=log（x）+log（2） log（8）+log（x）=log（24） 2log（x）=log(2x)+log(3) 已知log a x=2,log b x=1,log c x=4,求log abc x 的值 4^log(4)[x^2]+3^log(9)[6x]=log(2)[16] 第2第3项 怎么处理的?