cos(-20π/3)求过程

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cos(-20π/3)求过程cos(-20π/3)求过程cos(-20π/3)求过程cos(-20π/3)=cos(20π/3)=cos(6π+2π/3)=cos2π/3=-1/2=cos(-6π-2

cos(-20π/3)求过程
cos(-20π/3)求过程

cos(-20π/3)求过程

cos(-20π/3)=cos(20π/3)=cos (6π+2π/3)=cos 2π/3=-1/2

=cos(-6 π-2/3 π ) =cos(-2/3 π )=sin(7/6 π )=-sin( π/6 )=-1/2