sinx=1/2 siny=1/3 ,sin(x+y)(sinx-y)=?数学达人帮我啊·······
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/27 14:44:59
sinx=1/2siny=1/3,sin(x+y)(sinx-y)=?数学达人帮我啊·······sinx=1/2siny=1/3,sin(x+y)(sinx-y)=?数学达人帮我啊·······si
sinx=1/2 siny=1/3 ,sin(x+y)(sinx-y)=?数学达人帮我啊·······
sinx=1/2 siny=1/3 ,sin(x+y)(sinx-y)=?
数学达人帮我啊·······
sinx=1/2 siny=1/3 ,sin(x+y)(sinx-y)=?数学达人帮我啊·······
sin(x+y)sin(x-y)=[sinxcosy+cosxsiny][sinxcosy-cosxsiny]
=(sinxcosy)^2-(cosxsiny)^2
=(sinx)^2[1-(siny)^2]-[1-(sinx)^2](siny)^2
=1/4*(1-1/9)-(1-1/4)*1/9
=5/36
用积化和差公式:
sin(x+y)*sin(x-y)=cos(2y)-cos(2x)=1-2siny^2+(1-2sinx^2)=2-2(1/4+1/9)=23/18
已知sinx+siny=1/3,sinx-siny的最小值已知sinx+siny=1/3,sinx-已知sinx+siny=1/3,sinx-siny的最小值是
sinx+siny=1/3,则siny-(cosx)^2的最大值为?最小值为?
已知sinx+siny=1/3求siny-(cosx)^2的最小值和最大值
已知sinx+siny=1/3求siny-(cosx)^2的最小值
已知sinx+siny=1/3,求函数u=sinx—(cosy)^2的最值 u=1/3-siny-(1-siny^2)=siny2-siny-2/3=(siny-1/2)^2-11/12 -1
已知sinx+siny=1/3,求u=sinx-cos^2y的最值
已知sinx+siny=1/3,求sinx-(cos)^2的最大值,麻烦详细点.
已知sinx+siny=1/3求sinx-cos^2y的最大值和最小值
己知sinx+siny=1/3,求sinx+cos^2y的最大值和最小值
己知sinx+siny=1/3,求z=siny—cos^2 x的最大值.
己知sinx+siny=1/3,求z=siny—cos^2 x的最大值.
已知sinx+siny=1/3,求 siny-cos²x的最大值?
siny+sinx=1/3,则siny-cos²x的最大值为---,最小值为---
若3sinx*2+2siny*2=1 且3(sinx+cosx)*2+2(siny+cosy)*2=1求cos(2x+2y)
求y=(sinx)^2-cosx+2最值已知sinx+siny=1/3,求siny-(cosx)^2的最值
关于三角函数的计算已知SinX+SinY=2/3求 SinX-SinY=?怎么算?
已知sinx+siny=1/3求siny-(cosx)^2的最小值和最大值 求高人指点老师给的答案是: 因为sinx+siny=1/3即siny=1/3 -sinx且-1≤siny≤1则-1≤1/3 -sinx≤1即-1≤ sinx -1/3≤1-2/3≤sinx≤4/3又-1≤sinx≤1所以-2/3≤sinx≤
cosx+cosy=1/2,sinx-siny=1/3,则cos(x+y)=?