∫sin^8(x/2)dx
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 15:48:33
∫sin^8(x/2)dx∫sin^8(x/2)dx∫sin^8(x/2)dx∫[sin(x/2)]^8dx=∫[35/128-cosx/4+7cos(2x)/32+cos(4x)/128-cosx(
∫sin^8(x/2)dx
∫sin^8(x/2)dx
∫sin^8(x/2)dx
∫[sin(x/2)]^8dx=∫[35/128-cosx/4+7cos(2x)/32+cos(4x)/128-cosx(1-(sinx)^2)/4]dx
(应用倍角公式)
=∫[35/128-cosx/4+7cos(2x)/32+cos(4x)/128]dx-∫[cosx(1-(sinx)^2)/4]dx
=35x/128-sinx/4+7sin(2x)/64+sin(4x)/512-∫[(1-(sinx)^2)/4]d(sinx)
=35x/128-sinx/4+7sin(2x)/64+sin(4x)/512-sinx/4+(sinx)^3/12+C (C是常数).
∫sin^8(x/2)dx
∫sin(8x)dx
∫x/sin^2(x) dx
∫sin(x) cos^2(x)dx
∫sin^2x/(1+sin^2x )dx求解,
∫sin(6x)sin(2x)dx=?
∫(2/sin^2x)dx=
∫(1-sin^2( x/2))dx
求∫ sin^2 x/2 dx ..
求不定积分:∫sin(x^2)dx
求不定积分∫sin(x/2)dx
∫[(sin^2)x]dx求不定积分
∫(cosx/1+sin^2x)dx
∫sinx/(cosx-sin^2x)dx
∫sin(√2x)dx
∫ 4/sin^2x dx
∫sin^2x(1+tanx)dx
求∫sin(x^2)dx