cos[2arctan(-1/2)]=?
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cos[2arctan(-1/2)]=?cos[2arctan(-1/2)]=?cos[2arctan(-1/2)]=?可以设tan(X)=-1/2题目就转化成求cos2X用万能公式cos2X=1-(
cos[2arctan(-1/2)]=?
cos[2arctan(-1/2)]=?
cos[2arctan(-1/2)]=?
可以设tan(X)=-1/2 题目就转化成求cos2X
用万能公式 cos2X=1-(tanX)^2/1+(tanX)^2=1-(-1/2)^2/1+(-1/2)^2=3/5
0.6
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cos[2arctan(-1/2)]=?
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