〖lim〗┬(x→0) 1/x (sin⁡〖1/x〗-1/x)就是这个,/>

求极限lim┬(x→0)⁡〖(tan⁡x-sin⁡x)/ln⁡(1+x^3 ) 〗lim┬(x→0)⁡〖(x-sin⁡x)/x^3 〗 〖lim〗┬(x→0) 1/x (sin⁡〖1/x〗-1/x)就是这个,/> lim┬(x→1）〖(sin(x-1))/(x-1)〗 这道题怎么算 lim （x→0）x sin 1/x= lim┬(x→0)sinπx/(4(x-1)= lim(x→0)×(x-sin²3x)/x 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 lim→0 sin^3/x^3 证明lim(x→0)x*sin(1/x)=0我的证明如下:lim(x→0)x*lim(x→0)sin(1/x)因为lim(x→0)x为无穷小量.0 1.lim x→0 3x/(sinx-x)2.lim x→0 (1-cosmx)/x^23.lim x→0 sin4x/[(√x+2)-√2]4.lim h →0 [sin(x+h)-sin(x-h)]/h lim (x→0+)sin x/x= LIM(X→∞)X*SIN(1/X) 求极限,lim x趋于0 x * sin 1/x lim(x趋向0)ln(1+sin x)/x^2 求极限lim(x-->0)x^2 sin(1/x), 求极限 lim sin(x^2 * sin (1/x))/x x->0求极限 lim sin(x^2 * sin (1/x))/x x->0 lim(x→0) [1-cos(x^2)]/sin(x^2)tan(x^2)]=? lim x->0 (sin x-tan x)/sin (x^3)