若x+y+z=2,x2-(y+z)2=8,求x-y-z= x2为X的平方

若x+y+z=2,x2-(y+z)2=8,求x-y-z= x2为X的平方 己知x=2,y+z=1,求代数式x2(-y-z)+4x(z+y)的值. 若x+y+z=3y=2z,则x/x+y+z=? 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z 若x+y=6,xy=-8,求代数式(x+y-z)^2+(x+y-z)(x+y+z)-2·z(x-y) 若x-y=6,xy=-8,求代数式(x+y+z)²+(x-y-z)(x-y+z)-2·z(x+y)的值 已知x,y,z满足x/(y+z)+y/(z+x)+z/(x+y)=1,求代数式x2/(y+z)+y2/(x+z)+z2/(x+y)的值、2是平方 已知xyz不等于0,且{x+3y+5z=0 x2+3y+z=0,则x.x+y.y-2z.2z/3x.3x+2y.2y+z.z=? X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是 （y+z-2x)(x-2y+z)分之（x-z)(y-z) 用行列式的性质证明：y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证? 已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX.. 若x+y+z=2,x^2-（y+z）^2=8,则x-y-z=多少? 若x-y+z=-4,x^2-(y+z)^2=8,则x+y+z=如题 若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值 若x、y、z均不等于0,且2x+y-z=0 x+8y+2z=0,则x:y:z=? 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)