(X+Y)(X+Y-1)-12=0求X+Y=?
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(X+Y)(X+Y-1)-12=0求X+Y=?(X+Y)(X+Y-1)-12=0求X+Y=?(X+Y)(X+Y-1)-12=0求X+Y=?(x+y)(x+y-1)-12=0,(x+y)(x+y-1)=
(X+Y)(X+Y-1)-12=0求X+Y=?
(X+Y)(X+Y-1)-12=0求X+Y=?
(X+Y)(X+Y-1)-12=0求X+Y=?
(x+y)(x+y-1)-12=0,(x+y)(x+y-1)=12,假设x+y=4,x+y-1=3.看迩题目里面有没有说x≠y了.推算到这步了迩自己应该懂了,
(x+y)^2-(x+y)-12=0 (x+y-4)(x+y+3)=0 x+y=4或x+y=-3
(X+Y)(X+Y-1)-12=0求X+Y=?
/解答(x+Y)(x+Y-1)-12=0求X+Y
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