急 已知AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证1)△BAD≌△CAE 2)BD⊥CE

如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证：BE=DC非常急 已知,如图,AB⊥AC,AB=AC,AD⊥'AE,AD=AE,求证:(1)BE=CD;(2)BC⊥CD急!帮个忙呗! 急 已知AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证1)△BAD≌△CAE 2)BD⊥CE 如图,已知：AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证：ED⊥BC. 如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证：BE=DC 已知AD⊥AB,AE⊥AC,AD=AB,AE=AC,求证BE=DC ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd 如图,已知AD//BC,AD=BC,AE⊥AD,AF⊥AB,AE=AD,AB=AF.求证：AC=EF. 已知AD=AE,DM=EN,AD⊥DC,AE⊥EB.求证AB=AC 如图,AD⊥AE,AB垂直AC,AD=AE,AB=AC,AD⊥AE ,AB=AC,求证：三角形ABD≌三角形ACE 如图,已知AE⊥AD,AF⊥AB,AB//CD,AE=CD,AE=AD,AF=CD,求证AC=EF 已知AD⊥AB,AC⊥AE,且AD=AB,AC=AE.求证：DC⊥BE,DC=BE. 如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE,已知△DAC≌△EAB.求证BE⊥CD 如图,已知AB=AC,AB⊥AC,AD⊥AE且∠ABD=∠ACE,求证AD=AE 如图,已知：AB⊥AC,AD⊥AE,AB=AC,AD=AE,说明BE=DC的理由 已知AD是△ABC的中线AE⊥AB,AF⊥AC且AE=AB,AF=AC连接EF求证AD=1/2EF 已知AD是△ABC的中线AE⊥AB,AF⊥AC且AE=AB,AF=AC连接EF求证AD=1/2EF 已知AB=AC,AB⊥AC,AD=AE,AD⊥AE,点M为CD的中点,求证:AM=1/2BE