证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π/(2n+1))……cos(nπ/(2n+1))=1/2^n
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证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π/(2n+1))……cos(nπ/(2n+1))=1/2^n证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π
证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π/(2n+1))……cos(nπ/(2n+1))=1/2^n
证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π/(2n+1))……cos(nπ/(2n+1))=1/2^n
证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π/(2n+1))……cos(nπ/(2n+1))=1/2^n
详细过程请看图片,其中部分计算过程式子较长,但其实计算量不大,你细心算算看,如有错漏,请指正
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证明cos(π/(2n+1))cos(2π/(2n+1))cos(3π/(2n+1))……cos(nπ/(2n+1))=1/2^n
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