若sin2a=3/5,则sin^4a+cos^4a=
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若sin2a=3/5,则sin^4a+cos^4a=若sin2a=3/5,则sin^4a+cos^4a=若sin2a=3/5,则sin^4a+cos^4a=因为sin2a=3/5=2sinacosa,
若sin2a=3/5,则sin^4a+cos^4a=
若sin2a=3/5,则sin^4a+cos^4a=
若sin2a=3/5,则sin^4a+cos^4a=
因为sin2a=3/5=2sinacosa,sin²a+cos²a=1
所以sin^4a+cos^4a=(sin²a+cos²a)²-2sin²acos²a
=1²-sin2a/2
=1-9/50
=41/50
∵sin2a=3/5
∴sinacosa=3/10
sin^4a+cos^4a=(sin^2a+cos^2a)^2-2sin^2acos^2a
=1-2(sinacosa)^2
=1-2(3/10)^2
=41/50
若sin2a=3/5,则sin^4a+cos^4a=
sin2a=3/5,求sin a.
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