已知f(x)= (1/2)^x,x≥4； f(x+1), x＜4. 则f(log2³）=——————已知f(x)= (1/2)^x，x≥4； f(x)= f(x+1), x＜4. 则f(log2³）就是[以2为底3的对数]=——————

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已知f(x)=(1/2)^x,x≥4；f(x+1),x＜4.则f(log2³）=——————已知f(x)=(1/2)^x，x≥4；f(x)=f(x+1),x＜4.则f(log2³）

已知f(x)= (1/2)^x,x≥4； f(x+1), x＜4. 则f(log2³）=——————已知f(x)= (1/2)^x，x≥4； f(x)= f(x+1), x＜4. 则f(log2³）就是[以2为底3的对数]=——————
已知f(x)= (1/2)^x,x≥4； f(x+1), x＜4. 则f(log2³）=——————
已知f(x)= (1/2)^x，x≥4；
f(x)= f(x+1), x＜4. 则f(log2³）就是[以2为底3的对数]=——————

已知f(x)= (1/2)^x,x≥4； f(x+1), x＜4. 则f(log2³）=——————已知f(x)= (1/2)^x，x≥4； f(x)= f(x+1), x＜4. 则f(log2³）就是[以2为底3的对数]=——————
1

f(log2 3)=f(log2 3 +1)

log2³<4
f(log2³）=f(log2³+1）
log2³+1=log2(6)<4
f(log2(6)）=f(log2(6)+1）
log2(6)+1=log2(12)<4=log2(16)
f(log2(12）=f(log2(12)+1）
log2(12)+1=log2(24)>4
f(log2(24）=(1/2)^log2(24)=1/24
即
f(log2³）=1/24

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