求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
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求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值求1/x(x+1)+2/(x+1)(x+3)+3/(
求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
求1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)的值
1/x(x+1)+2/(x+1)(x+3)+3/(x+3)(x+6)
=1/x-1/(x+1)+1/(x+1)-1/(x+3)+1/(x+3)-1/(x+6)
= 1/x-1/(x+6)
=(x+6-x)/[x(x+6)]
=6/[x(x+6)]
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