3^n乘以sin(π/3^n) n趋向于无穷时 求极限!

3^n乘以sin(π/3^n) n趋向于无穷时 求极限! 当n趋向于无穷大时,n{sin(1/n)-sin[1/(n+1)]}趋向 lim 1/n(sinπ/n+sin2π/n+.+sinnπ/n) n 趋向于正无穷 lim i/n(sinπ/n+sin2π/n+.+sinnπ/n) n 趋向于正无穷 lim(n趋向无穷)nπ*sin(nπ) lim nsin(3x/n)=?n趋向于无穷大 n趋向于无穷 lim π^n/2^n+3^n.求极限lim n趋向于正无穷大.具体解算, lim π^n/(2^n+3^n).求极限lim n趋向于正无穷大.具体解算, lim x趋向于无穷 (2^n+1+3^n+1)/(2^n+3^n)= 求lim趋向于无穷3^n+(-2)^n/3^(n+1)+(-2)^(n+1) lim(x趋向于无穷)2^n-3^n/2^n+3^n lim(n趋向于无穷大 )(5n平方+n-2)/(3n平方-2) 求极限(n+4/n+3)∧2n.n趋向于无穷大 (1+2^n+3^n)^(1/n) 其中n趋向于正无穷 求一下y=sin(nπ) 的极限?当n趋向于无穷大时! lim(2^n+3^n)^1 (n趋向无穷) 请教一个极限题,lim（n趋向于无穷大）2的n次方乘以sin（x比2的n次方） 等于多少啊?