lim(n趋向无穷)nπ*sin(nπ)

lim(n趋向无穷)nπ*sin(nπ) lim 1/n(sinπ/n+sin2π/n+.+sinnπ/n) n 趋向于正无穷 lim i/n(sinπ/n+sin2π/n+.+sinnπ/n) n 趋向于正无穷 lim( sinnπ/n) ,当n趋向无穷时 lim(x趋向无穷)(sin n)/n=? lim sin(根号 (n+1)= 根号 (n-1))π,n趋向于无穷lim sin(根号 (n+1)- 根号 (n-1))π,n趋向于无穷 等号是减号 紧急：求 lim n*sin(π(n^2+2)^0.5）*(-1)^n,n趋向无穷大； lim(2^n+3^n)^1 (n趋向无穷) lim(100sin(n!))/(2n-1)n趋向于+无穷.大一高数题. (1)lim(x趋向0)[(1+x)^0.5+(1-x)^0.5-2]/x^2 (2)lim(n趋向无穷)sin[[(n^2+1)^0.5]π](1)lim(x趋向0)[(1+x)^0.5+(1-x)^0.5-2]/x^2 (2)lim(n趋向无穷)sin[[(n^2+1)^0.5]π] 求lim(n趋向于正无穷)(x^n)/n! 3^n乘以sin(π/3^n) n趋向于无穷时 求极限! lim n 趋向于正无穷的时候sin（派/n）是多少 lim x趋向于无穷 2^n sin(x/2^n) 求极限 n*sin(x/n) n趋向无穷 lim n趋向于无穷 2^n sin(x/2^n)X为不等于0的常数 lim(sin(1/x)/(1/x)) n-趋向无穷怎么解 lim(n趋向于无穷)(x-a)sin(1/a-x)