∫sin(2x-π/6)cos(3x+π/6)dx

已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x 为什么cos(2x-π/3)-sin(5π/6) =cos(2x-π/3)? ∫sin(2x-π/6)cos(3x+π/6)dx cos(x+π/3)是不是等于sin(x-π/6) cos(π/6-x)=sin(π/3+x)?为什么 求证 tan（2π-X）sin（-2π-X）cos（6π-X）/ sin（X+3π/2)*cos（X+3π/2)=-tanX 已知函数f（x）=［2sin（x-π/6）+√3sin x］cos x+sin^2x,x∈R 已知F(X)=根号3COS^2 X+SIN XCOS X-2SIN X*SIN(X-π/6),求F(X)的最大值 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 求值sin²x+cos²(π/6+x)+1/2sin(2x+π/6) 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 函数Y=sin(2x+π/3)cos(x-π/6)-cos(2x+π/3)sin(x-π/6)的图像的一条对称轴方程是多少 已知sin(x+π/3)=1/4,求sin(2π/3-x)+cos²(π/6-x) sin cos之间怎么转换?sin(π/3-2X）等于cos多少? 2(sin^6x+cos^6)-3(sin^4x+cos^4x) 化简sin(x+7π/4)+cos(x-3π/4）步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2- 设f(x)=(sin^2(6π+x)+cosx-2cos^3(3π+x)-3)/2+cos^2(x-4π)-cos(-x)设f（x）=（sin^2(6π+x）+cosx-2cos^3(3π+x）-3）/2+cos^2（x-4π）-cos（-x）求f（π/3）的值