(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=
来源：学生作业帮助网 编辑：六六作业网 时间：2024/07/24 14:00:45
(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=(x^4
(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=
(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=
(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=
(x^4n+16)(x^n-2)(x^2n+4)(x^n+2）
=(x^4n+16)(x^2n+4）(x^2n-4)
= (x^4n+16）(x^4n -16）
= x^8n+16²
= x^8n+256
(x^2n-2)(x^8n+16)(x^2n+2)(x^4n+4)
(x^4n+16)(x^n-2)(x^2n+4)(x^n+2)=
(x^4n - 16) * (x^n - 2) * (x^2n + 4) * (x^n + 2)
(x^4n/x^2n)*x^n
x^(n)*x^(n+1)+x^(2n)*x
因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)
因式分解4x^n+2-9x^n+6x^n-1-x^n-2
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)
x^n-1(3x^n+4x^n+1-5x^n+2)
因式分解：x^(2n)+(2x)^(n)+4^(n-1)
x^2n+(2x)^n+4^(n-1) 因式分解
2x^n-16x^n-2+32x^n-4因式分解
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
16-x^n=【4＋x²】【2＋x】【2-x】求n
若(x^2+1/x)^n(n∈N+,n
因式分解：(x^n+1)+(2x^n)+(x^n-1)
x^n+1-2x^n+x^n-1因式分解
x^n-1-2x^n+x^n-1因式分解