根号2加根号3加根号6乘以根号2减根号3加根号6

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根号2加根号3加根号6乘以根号2减根号3加根号6根号2加根号3加根号6乘以根号2减根号3加根号6根号2加根号3加根号6乘以根号2减根号3加根号6解(√2+√3+√6)(√2-√3+√6)=[(√2+√

根号2加根号3加根号6乘以根号2减根号3加根号6
根号2加根号3加根号6乘以根号2减根号3加根号6

根号2加根号3加根号6乘以根号2减根号3加根号6

(√2+√3+√6)(√2-√3+√6)
=[(√2+√6)+√3][(√2+√6)-√3]
=(√2+√6)²-(√3)²
=2+4√3+6-3
=5+4√3

=[(√2+√6)+√3][(√2+√6)-√3]
=(√2+√6)²-(√3)²
=2+2√12+6-3
=5+4√3