tana=1\2,4sin^2a+2sina*cosa-1
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tana=1\2,4sin^2a+2sina*cosa-1tana=1\2,4sin^2a+2sina*cosa-1tana=1\2,4sin^2a+2sina*cosa-12sina=cosa,2s
tana=1\2,4sin^2a+2sina*cosa-1
tana=1\2,4sin^2a+2sina*cosa-1
tana=1\2,4sin^2a+2sina*cosa-1
2sina=cosa,2sina*cosa=cos²a,4sin²a=cos²a=1-sin²a,5sin²a=1,sin²a=1/5,4sin^2a+2sina*cosa-1=4sin²a+cos²a-1=3sin²a=3/5.
特殊法代入 =w=
证明cos^4 a-sin^4 a=cos^2(1-tana)(1+tana)
证明sin^4 a+cos^4 a=cos^2(1-tana)(1+tana)
tanA=2 求(sin^2 A+ sinAcosA)/(tanA+1+sin^2 A) 急 .
求证sin^2a*tana+cos^2a*1/tana+2sina*cosa=tana+1/tana
k=(2sin^2a+sin2a)/(1+tana) 则sin(a-3.14/4)的值
tana=2 sin平方a=
求证1+2sina cosa/sin^2a-cos^2a=tana+1/tana-1
(1-2sinAcosA)/(cos^2A-sin^2A)=(1-tanA)/(1+tanA)
证明(1-2sinAcosA)/(cos^2A-sin^2A)=(1-tanA)/(1+tanA)
求证:(1-tana)/(1+tana)=(1-2sinacosa)/(cos^2×a-sin^2×a)
cos^2a-sin^2a/1+2sinacosa=1-tana/1+tana怎么证明?
已知(tana-1)/tana=-1 求1/sin^2a+2sinacosa-cos^2a
求证:1+2sina cosa /sin^2a -cos^2a = tana +1/tana -1.
tanA=1/ tanA=sinA/ cotA=cosA/ sin^2A+cos^2A=
cos平方A-sin平方A/1+2sinAcosA=1-tanA/1+tanA
已知sin(π+a)=-1/2且tana
已知(2sin^a+sin2a)/(1+tana)=k (0
tana/2+tana/2=5/2,求sin(a-pai/3)1