23.设f(x,y)=x(xy-cosy),则∂^2f(x,y)/∂x∂y=

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23.设f(x,y)=x(xy-cosy),则∂^2f(x,y)/∂x∂y=23.设f(x,y)=x(xy-cosy),则∂^2f(x,y)/ͦ

23.设f(x,y)=x(xy-cosy),则∂^2f(x,y)/∂x∂y=
23.设f(x,y)=x(xy-cosy),则∂^2f(x,y)/∂x∂y=

23.设f(x,y)=x(xy-cosy),则∂^2f(x,y)/∂x∂y=
f(x,y)=x^2 *y -x*cosy
所以
∂f/∂x
=2xy -cosy
那么
∂²f/∂x∂y
=∂(2xy -cosy) /∂y
=2x +siny