(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.34)=多少,老兄看不懂!请仔细一点
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 11:24:49
(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.34)=多少,老兄看不懂!请仔细一点
(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.34)=多少,
老兄看不懂!请仔细一点
(1+0.23+0.34)x(0.23+0.34+0.65)-(1+0.23+0.34+0.65)x(0.23+0.34)=多少,老兄看不懂!请仔细一点
设1+0.23+0.34+0.65=a
原式
=(a-0.65)(a-1)-a(a-1-0.65)
=a^2-a-0.65a+0.65-a^2+a+0.65a
=0.65
设0.23+0.34=x
0.23+0.34+0.65=y
(1+0.23+0.34)*(0.23+0.34+0.65)-(1+0.23+0.34+0.65)*(0.23+0.34)
=(1+x)y-(1+y)x
=y+xy-x-xy
=y-x
=0.65
设:1+0.23+0.34=a; 0.23+0.34=b;
(1+0...
全部展开
设0.23+0.34=x
0.23+0.34+0.65=y
(1+0.23+0.34)*(0.23+0.34+0.65)-(1+0.23+0.34+0.65)*(0.23+0.34)
=(1+x)y-(1+y)x
=y+xy-x-xy
=y-x
=0.65
设:1+0.23+0.34=a; 0.23+0.34=b;
(1+0.23+0.34)*(0.23+0.34+0.65)-(1+0.23+0.34+0.65)*(0.23+0.34)
=a×(b+0.65)-(a+0.65)×b
=ab+0.65a-ab-0.65b
=0.65×(a-b)…………因为:a=1+0.23+0.34;b=0.23+0.34
=0.65×(1+0.23+0.34-0.23-0.34)
=0.65×1
=0.65
设A=0.23+0.34
原式
=(1+A)*(A+0.65)-(1+A+0.65)*(A)
=A²+A+0.65A+0.65-A²-A-0.65A
=0.65
收起