如果xp-2+4x3-（q-2）x2-2x+5是关于x的五次...- - 菁品...

如果xp-2+4x3-（q-2）x2-2x+5是关于x的五次...- - 菁品... 若xP+4x3-qx2-2x+5是关于x的五次四项式,则q-p= 线性方程,求和（高数）n = 1 时, x1 = a（常数）, y1 = x1 * 0.1；n = 2 时, x2 = x1 + y1, y2= x2 *0.1n = 3 时, x3 = x2+y2 , y3= x3 * 0.1n = 4 时, x4 = x3+y3 , y4= x4 * 0.1求：n = p时, xp ,yp 的值.---------- 线性方程,求和（高数）n = 1 时,x1 = a（常数）,y1 = x1 * 0.1；n = 2 时,x2 = x1 + y1,y2= x2 *0.1n = 3 时,x3 = x2+y2 ,y3= x3 * 0.1n = 4 时,x4 = x3+y3 ,y4= x4 * 0.1求：n = p时,xp ,yp 的值.-------------------------------再追加50 用初等行变换来解下列线性方程组（1）2x1-x2+3x3=3 3x1+x2-5x3=0 4x1-x2+x3=3 x1+3x2-13x3=-6(2) x1-2x2+x3+x4=1 x1-2x2+x3-x4=-1 x1-2x2+x3-5x4=5(3) x1-x2+x3-x4=1 x1-x2-x3+x4=0 x1-x2-2x3+2x4=-1/2 已知在(x2+px+q)(x2-2x-3)的积中不含x2,x3项,求p,q的值 x3+x+2 x3-4x2-4x-5 因式分解 因式分解（1+x+x2+x3)2-x3 解方程组 X1-X2-4X3=-1 X2+X3=2 X1+X2-2X3=3线性代数 1.证明（8-7x-6x2+x3）+(x3+5x2+4x-1)-(-x2-3x+2x3-3)的值与x无关.快, 2x3+3x2-4x-1 max Z=2X1+4X2-5X3 X1+X2+X3=7 2X1-3X2+X3≥10 X1.X2.X3≥0 用配方法化二次型刘老师您好：f（x1,x2,x3）=x1^2+3x2^2+8x3^2+4x1x2+6x1x3+10x2x3配方后得f（x1,x2,x3）=（x1+2x2+3x3）^2-(x2+x3)^2 做可逆线性变换y1=x1+2x2+3x3 x1=y1-2y2-y3y2=x2+x3 即 x2=y2-y3y3=x3 x3=y3「即」前面的式 若xp + 4x3 - qx2 - 2x + 5是关于x五次五项式,则-p = .若xp + 4x3 - qx2 - 2x + 5是关于x五次五项式,则-p = .怎么算?根据什么?为什么? 若xP+4x3+qx2+2x+5是关于x的五次四项式,则qp= lim_x→无穷(x3+2x2+x/2x3-x2) (x2+4x+4)/(x3+2x2-4x-8) x3+2x2+xy2因式分解