设π/4
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设π/4设π/4设π/4左边=cos(α+β)cos(π/4-β)-sin(α+β)sin(π/2-(π/4+β))=cos(α+β)cos(π/4-β)-sin(α+β)sin(π/4-β)=cos
设π/4
设π/4
设π/4
左边=cos(α+β)cos(π/4-β)-sin(α+β)sin(π/2-(π/4+β))
=cos(α+β)cos(π/4-β)-sin(α+β)sin(π/4-β)
=cos(α+β+π/4-β)
=cos(α+π/4)=-4/5
所以cosα+sinα=-4/5*2½
两边平方,得1+2cosαsinα=32/25
sin2α=7/25
剩下不用我做了吧,把我做累死了.应该没什么问题,给分吧~