已知f(x)=log3x,求证f(x)+f(y)=f(xy)

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已知f(x)=log3x,求证f(x)+f(y)=f(xy)已知f(x)=log3x,求证f(x)+f(y)=f(xy)已知f(x)=log3x,求证f(x)+f(y)=f(xy)f(x)+f(x0=

已知f(x)=log3x,求证f(x)+f(y)=f(xy)
已知f(x)=log3x,求证f(x)+f(y)=f(xy)

已知f(x)=log3x,求证f(x)+f(y)=f(xy)
f(x)+f(x0
=log3(x)++log3(y)
=log3(xy)
=f(xy)

这个证明不对啊,应该是f(x) + f(y) < f(xy) 啊
f(x) + f(y)
= log3x + log3y
= log(3x*3y)
= log(9xy)
= log3 + log(3xy)
< log(3xy)=f(xy)