(2/3ab^2-2ab)×1/2ab

3ab(ab的平方+2ab) 5ab-2[3ab-(4ab²+2分之1ab)]-5ab² (2/3ab^2-2ab)*1/2ab (2/3ab^2-2ab)×1/2ab ab-[3ab-(4ab^2+1)]-4ab^2化简.（要有过程） ab-[3ab-(4ab^2+1)]-4ab^2化简. 计算:(3ab^2)^2 + (-4ab^3) * (-ab) a^2-3ab+b^2/ab=( )/ab-3 a^2-3ab+b^2/ab=( )/ab -3 3(a2-2ab)-(-ab+b2)+(2ab+b2) (ab+1)2-(ab-1)2为什么会等于(ab+1+ab-1)(ab+1-ab+1) 计算(-2ab)×3ab= 2ab+3ab等于多少? 已知（a-2）+（b+1）=0,求多项式3ab+ab-3ab+5ab+ab+2分之1ab [(3ab-2)(3ab+2)+(2ab+2)²]/5ab= [(3ab-2)(3ab+2)+(2ab+2)²]/5ab= v a^2b-ab+2ab^2-5a^b-4ab+3ab^2化简快 2(a²b+ab)-2(ab²-1)-2ab²-2ab 化简就行了