lim (n→∞) [(-2)^(n+1)/(1-2+4+...+(-2)^n),
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lim(n→∞)[(-2)^(n+1)/(1-2+4+...+(-2)^n),lim(n→∞)[(-2)^(n+1)/(1-2+4+...+(-2)^n),lim(n→∞)[(-2)^(n+1)/(1
lim (n→∞) [(-2)^(n+1)/(1-2+4+...+(-2)^n),
lim (n→∞) [(-2)^(n+1)/(1-2+4+...+(-2)^n),
lim (n→∞) [(-2)^(n+1)/(1-2+4+...+(-2)^n),
lim (n→∞) (-2)^(n+1)/(1-(-2)^n+1)/1+2=lim (n→∞) 3(-2)^(n+1)/1-(-2)^(n+1)=lim (n→∞) 3/1/(-2)^(n+1)-1=-3
大哥,回答了好多遍了 答案是6啊,我肯定!
[(-2)^(n+1)/(1-2+4+...+(-2)^n)]
=(-2)^(n+1)/[(1-(-2)^n)/(1-(-2))]
=[(-2)^(n+1)*3/(1-(-2)^n)) 同除以(-2)^n
=(-2)*3/(1/(-2)^n-1) 让n趋向无穷大
=6
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