Lim(x→∞)(√x2+2x-x)求极值
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Lim(x→∞)(√x2+2x-x)求极值Lim(x→∞)(√x2+2x-x)求极值Lim(x→∞)(√x2+2x-x)求极值lim(x->∞)[√(x²+2x)-x]=lim(x->∞){
Lim(x→∞)(√x2+2x-x)求极值
Lim(x→∞)(√x2+2x-x)求极值
Lim(x→∞)(√x2+2x-x)求极值
lim(x->∞)[√(x²+2x)-x]=lim(x->∞){[(x²+2x)-x²]/[√(x²+2x)+x]} (有理化分子)
=lim(x->∞){2x/[√(x²+2x)+x]}
=lim(x->∞){2/[√(1+2/x)+1]} (分子分母同除x)
=2/[√(1+0)+1]
=1.
所以极限值不存在
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