∫sin^2xdx

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∫sin^2xdx∫sin^2xdx∫sin^2xdx答：由cos2x=1-2(sinx)^2得：(sinx)^2=1/2-cos2x/2∫(sinx)^2dx=∫1/2-cos2x/2dx=x/2-

∫sin^2xdx
∫sin^2xdx

∫sin^2xdx
答：
由cos2x=1-2(sinx)^2得：(sinx)^2=1/2-cos2x/2
∫(sinx)^2dx
=∫ 1/2-cos2x/2 dx
=x/2-sin2x/4 + C

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