解不等式-1/2
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/18 10:11:31
解不等式-1/2解不等式-1/2解不等式-1/2[-π/6+2kπ,π/3+2kπ)∪(2π/3+2kπ,7π/6+2kπ](k∈Z)-1/2≤sinx≤√3/22kπ-π/6≤x≤2kπ+π/3【解
解不等式-1/2
解不等式-1/2
解不等式-1/2
[-π/6+2kπ,π/3+2kπ)∪(2π/3+2kπ,7π/6+2kπ] (k∈Z)
-1/2≤sinx≤√3/2 2kπ-π/6≤x≤2kπ+π/3 【解析】sin(2kπ-π/6)=-1/2 sin(2kπ+π/3)=√3/2 1）π/3≤x≤2π/3 2)