以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8
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以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)
以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8
以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8
以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8
因为x+y+z=1
所以
(1+1/x)(1+1/Y)(1+1/z)=(1+1/x)(1+1/Y)(1+1/z)(x+y+z)(x+y+z)(x+y+z)=[x+y+z+1+(y+z)/x][x+y+z+1+(x+z)/y][x+y+z+1+(x+y)/z]=[2+(y+z)/x][2+(x+z)/y][2+(x+y)/z]=8+后面的余项>8
即得证
以知X+Y+Z=1求证(1+1/x)(1+1/Y)(1+1/z)>8
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