Limx→0y→0sin(xy)/y
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/17 17:51:18
Limx→0y→0sin(xy)/yLimx→0y→0sin(xy)/yLimx→0y→0sin(xy)/y
Limx→0y→0sin(xy)/y
Limx→0y→0sin(xy)/y
Limx→0y→0sin(xy)/y
Limx→0y→0sin(xy)/y
limx趋近于0y趋近于0sin(xy)/x求极限.
求下列极限 1.lim x→0y→2 sin(xy)/x 2.lim x→0y→0 (2-√(xy+4))/xy3.lim x→0y→0(x^2y)/(x^3-y^3) 4.limx→0y→1 xy*sin(1/(x^2+y^2))
limx->0,y->0(xy/(x^2+y^2))^2
limx趋近0,y趋近0 (x^2+y^2)^xy
当(x,y)→(0,2)时,sin xy/xy的极限为?
x→2,y→0,求lim sin[(8 -x)y]/xy=多少呀?
limx→2 y→0 ln(x+e*y)/根号(x*2+y*2)
limx→0 sin[sin(sinx)]/x
x→0,y→0 [2-√(xy+4)]/xy的极限.x→2,y→0 sin(xy)/y的极限
limx→0 tan(tanx)-sin(sinx)/x^3
limx→0x/Sin(x/2)的极限是什么
limx→0[sinx-sin(sinx)]sinx/x^4
limx→0(sin³x/sinx³)=
当(x,y)→(0,2),求sin xy/x的二重极限!详细步骤啊.
lim x→0y→2 sin(xy)/x 求极限值解题时为什么把sin直接省去了
求极限limx→0 (cosx)^1/sin^2x求极限limx→0 (cosx)^(1/sin^2x)
xy-sin(πy^2)=0 求dy/dx