化简1/(sin^2 a-cos^2 a)
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化简1/(sin^2a-cos^2a)化简1/(sin^2a-cos^2a)化简1/(sin^2a-cos^2a)1/(sin²a-cos²a)=1/[-(cos²a-s
化简1/(sin^2 a-cos^2 a)
化简1/(sin^2 a-cos^2 a)
化简1/(sin^2 a-cos^2 a)
1/(sin²a-cos²a)
=1/[-(cos²a-sin²a)]
=1/[-cos(2a)]
=-sec(2a)
sin^2a+cos^2a/sin^2a-cos^2a
化简Sin A + Sin 2A / 1+cos A +
求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
sin a+sin 2a /1+cos a+cos 2a 化简.
化简 1-sin^4a-cos^4a/cos^2a-cos^4a
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
化简(sin a^2/cos a +cos a)*cot a
化简 (1+sin a+ cos a)(sin a/2 - cos a/2) / √(2+2cos a)(180°
求证:sin 2a/1+sin a+cos a=sin a+cos a-1急
sin^2(a+pai)-cos(pai+a)*cos(-a)+1
(1-sin^4a-cos^4)/(sin^2a-sin^4a) 化简
化简:sin(-a)cos(2π+a)sin(-a-π)
证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a
化简sin^2a-cos^2a
化简sin(a/2)cos(a/2)
求证 1+sin a+cos a+2sin a*cos a/1 +sin a +cos a = sin a+ cos a 有什么思路!
化简cos(a+b)cos(a-b)+sin^2b
化简1/(sin^2 a-cos^2 a)
化简sin(1/2π-a)是不是cos(a)