f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=

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f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=f(x)=asinx+btanx+1,f(5)=

f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=
f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=

f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)=
f(x)=asinx+btanx+1,f(5)=7,
则f(2010π-5)
=-asin5-btan5+1
=-asin5-btan5+1
=-asin5-btan5+1
=-(asin5+btan5+1)+2
=-f(5)+2
=-7+2=-5

∵函数f (x )=asinx+btanx+1
∴f(5)=asin5+btan5+1=7
∴asin5+btan5=7-1=6
∵f(2010π-5)=f(-5)=-asin5-btan5+1
∴f(-5)=-(asin5+btan5)+1=-6+1=-5
则f(2010π-5)=-5
【sin(2010π-5)=sin(-5),tan(2010π-5)=tan(-5)】