函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___

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函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___函数f(x)=asinx+btanx+1满足f（

函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___
函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___

函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___
f(5)=asinx+btanx+1=7
asinx+btanx=7-1=6
f(-(5))=asin(-x)+btan(-x)+1
=-asin(x)-b(tanx)+1
=-(asinx+btanx-1)
=-(6-1)
=-5

f(X)=asinx+btanx+1 求其最小正周期函数f(x)=asinx=btanx+1满足f(5)=7,则f(-5)= 函数f(x)=asinx+btanx+1满足f（5）＝7则f(-5)＝___ 已知f（x)=asinx+btanx+2,f（1）=5,则f(-1)= 已知f(x)=asinx+btanx+1,满足f(5)=7,则f(-5)=? f(x)=asinx+btanx+1 f(2)=4 f(-2)=?原因? f(x)=asinx+btanx+1,f(5)=7,则f(2010π-5)= f（x）=asinx+btanx+1,若f（5）=7,则f（-5）= 已知f(x)=asinx+btanx+1满足f(兀/5)=7.求f(99兀/5) 1.已知函数发f(x)=asinx+btanx+1满足f(5)=7,则f(-5)的值为( ）2．f(cosx=cos3x,那么f(sin30度）的值为（）高一数学问题：已知函数f(x)=asinx+btanx+5,且f(3)=7,则F(-3)=________.感激不尽! 已知fx=asinx+btanx+1满足f(pia/5)=7 已知asinx+btanx+1且f(-2)=4、那么(π+2)等于多少若函数f(x)=asin2x+btanx+1,且f(2)=5,则f(π-2)+f(π)= 若函数F(X)=aSIN2X+bTANX+1,F（-3）=5,则F（3）=? 若函数f(x)=αsin2x+btanx+1,且f(－3)=5,则f(π+3)=? 若函数f(x)= asin2x+btanx+1,且f(-3)=5,则f(π+3）=? 若函数f（x）=asin2x+btanx+1,且f(-3)=5,求f(π+3）?