已知实数想x,y满足条件x-y+5>=0 x+y>=0 x

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已知实数想x,y满足条件x-y+5>=0x+y>=0x已知实数想x,y满足条件x-y+5>=0x+y>=0x已知实数想x,y满足条件x-y+5>=0x+y>=0x|z-1+2i|的最小值即求t=根号下

已知实数想x,y满足条件x-y+5>=0 x+y>=0 x
已知实数想x,y满足条件x-y+5>=0 x+y>=0 x

已知实数想x,y满足条件x-y+5>=0 x+y>=0 x
|z-1+2i|的最小值
即求t=根号下[(x-1)^2-(y+2)^2]的最小值
注意到t^2=(x-1)^2-(y+2)^2是圆心在[1,-2],半径为t的圆
x-y+5>=0 x+y>=0 x

好题!