x/2+y/3=2x/2+z/4=3y/3+z/4=1
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x/2+y/3=2x/2+z/4=3y/3+z/4=1x/2+y/3=2x/2+z/4=3y/3+z/4=1x/2+y/3=2x/2+z/4=3y/3+z/4=1三个未知数三个方程,用消元法.两边同时
x/2+y/3=2x/2+z/4=3y/3+z/4=1
x/2+y/3=2
x/2+z/4=3
y/3+z/4=1
x/2+y/3=2x/2+z/4=3y/3+z/4=1
三个未知数三个方程,用消元法.
两边同时乘以6 3x+2y=12 (1)
两边同时乘以4 2x+z=12 (2)
两边同时乘以12 4y+3z=12 (3)
(2)*3-(3)得,6x-4y=24,即3x-2y=12 (4)
(1)+(4)得,6x=24
x=4
所以y=0
带入(3)可得z=4
我要感谢你,让我复习了一把,
给点分吧
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