求值,-√2.89,±√121/25,0.0196±√(-5)^2+12^2,√41^2-40^2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 17:43:36
求值,-√2.89,±√121/25,0.0196±√(-5)^2+12^2,√41^2-40^2求值,-√2.89,±√121/25,0.0196±√(-5)^2+12^2,√41^2-40^2求值
求值,-√2.89,±√121/25,0.0196±√(-5)^2+12^2,√41^2-40^2
求值,-√2.89,±√121/25,0.0196
±√(-5)^2+12^2,√41^2-40^2
求值,-√2.89,±√121/25,0.0196±√(-5)^2+12^2,√41^2-40^2
-√2.89=-1.7
±√121/25=±11/5
,√0.0196=0.14
±√(-5)^2+12^2=±13
√41^2-40^2=9
求值,-√2.89,±√121/25,0.0196±√(-5)^2+12^2,√41^2-40^2
求值:arccos(-√3/2)
求值:√0.36=( );±√121/196=( ).
求值:cos(arcsin√3/2)=
求值arcsin(-√2/2)=
求值:arcsin(√3/3)=
求值tan(arcsin√2/2)
先化简再求值,a=1+√2
求值:arcsin(-√3/2)=
求值:(tan10°-√3)sin40°
求值:(tan10°-√3)sin40°
求值:1/sin10-√3/cos10
tan19+tan41+√3tan19tan41求值
求值:1.√1/b^2 (b
√8求值或化简
求值:cos40*[1+(√3)tan10]
定积分求值问题∫x^2√(1-x^2 )dxa=0 b=1 为积分的上下限求值
化简求值(数学)先化简,再求值:,其中x=√2