cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)的值为多少?
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cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)的值为多少?cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)的值为多少?cos(α-
cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)的值为多少?
cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)的值为多少?
cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)的值为多少?
cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)
=cos(α-38°-22°-α)
=cos-60
=cos60°°
=1/2
运用三角函数两角和公式:cos(α-β)=cosαcosβ+sinαsinβ
cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)
=cos[α-38°-(22°+α)]
=cos(-60°)
=cos60°
=1/2
根据余弦定理公式cosαcosβ+sinαsinβ=cos(α-β);
所以cos(α-38°)cos(22°+α)+sin(α-38°)sin(22°+α)
=cos(α-38°-22°-α)
=cos(-60º)
=cos(60°)
=1/2
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