f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
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f(x)=x(x-1)(x-2)…(x-99)(x-100),求f''(100)f(x)=x(x-1)(x-2)…(x-99)(x-100),求f''(100)f(x)=x(x-1)(x-2)…(x-99
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
f(x)=x(x-1)(x-2)…(x-99)(x-100),求f'(100)
∵f’(x)
=(x-100)’x(x-1)…(x-99)
+(x-100)[x(x-1)…(x-99)]’
而当x=100时,不管中括号的导数的值怎样,上式的第二部分积为0
∴f’(100)=100×99×…×1
=100!
f（100）=100×99×98×97……×1×0
＝0
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