求了limit(x→2/π) (sinx-1)tanx
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求了limit(x→2/π)(sinx-1)tanx求了limit(x→2/π)(sinx-1)tanx求了limit(x→2/π)(sinx-1)tanx(sinx-1)*tanx[x-->π/2]
求了limit(x→2/π) (sinx-1)tanx
求了limit(x→2/π) (sinx-1)tanx
求了limit(x→2/π) (sinx-1)tanx
(sinx-1)*tanx [x-->π/2]
==>[sin(x+π/2)-1]*tan(x+π/2) [x-->0]
即,[cosx-1]*(-cotx)[x-->0]
=-1/2x^2(-1/x)
=1/2x
=0.
应该是x趋进于二分之派吧,答案0
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