f(x,y,z)=z/(x^2+y^2+1)的定义域图像什么?他为什么是既开又闭点集?

分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y) f(x,y,z)=(x^2+y^2)^0.5+z^1.5,求 ∂f(x,y,z)/∂y 设z=f(x^2-y^2,e^（xy)),求偏导z/x,偏导z/y 用行列式的性质证明：y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证? (x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是 （y+z-2x)(x-2y+z)分之（x-z)(y-z) 设f(x,y,z)=e^x*y*z^2,其中z=z(x,y)是由x+y=z+x*e^(z-x-y)确定的隐函数,则f'x(0,1,1)= 设z=f(x^2,y,y/x)可导,求δz/δx,δz/δy 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知：x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值. x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 设函数f可微,z=f(ye^x,x/(y^2)) 求z/x,z/y 一道函数不等式题求出所有这样的函数f:R-R,使得对于一切x,y,z∈R,有f(x+y)+f（y+z）+f(x+z)=3f(x+2y+3z)f(x+y)+f（y+z）+f(x+z)=3f(x+2y+3z)改为f(x+y)+f（y+z）+f(x+z)≥3f(x+2y+3z) 高数求梯度设函数f(x,y,z)=(x-y)2+(y-z)2+(z-x)2,求gradf(x,y,z).我算对了吗 (x+y-z)^2-(x-y+z)^2=? (x-y-z)*( )=x^2-(y+z)^2 填空 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z) 计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)