tan2a=3,求(cos^2a-sin^2a)/sinacosa
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/27 18:28:50
tan2a=3,求(cos^2a-sin^2a)/sinacosatan2a=3,求(cos^2a-sin^2a)/sinacosatan2a=3,求(cos^2a-sin^2a)/sinacosa(
tan2a=3,求(cos^2a-sin^2a)/sinacosa
tan2a=3,求(cos^2a-sin^2a)/sinacosa
tan2a=3,求(cos^2a-sin^2a)/sinacosa
(cos^2a-sin^2a)/(sinacosa)
=(1-sin^2a-sin^2a)/(sinacosa)
=2(1-2sin^2a)/(2sinacosa)
=2(cos2a)/(sin2a)
=2/[tan2a]
=2/3
tan2a=3,求(cos^2a-sin^2a)/sinacosa
已知tan2a =3求(cos²a -sin²a )÷sina cosa
设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4)
已知tana=2,求sin(四分之π+a)/cos(四分之π+a)*tan2a的值
已知cosa=-5/13,a属于(π,3π/2),求sin(a-π/4),cos(a-π/4),tan2a.
已知sin=1/3 ,a∈(π/2 ,π),求cosa,tana ,sin2a ,cos2asin(π- a) ,cos(a+π) ,sin(a- π/3 ) ,tan( a -π/4) ,sin(π/2 +a) ,tan2a急,会的帮个儿
设sina=-3/5,a是第三象限角,求sin 2a,cos2a,tan2a.
[(tana*tan2a)/(tan2a-tana)]+√3(sin ^2 a-cos^2 a)=2sin [2a-(pi/3)]要过程,
tana=1/2,求tan2a和sin(2a+派/3)
已知tan(π/4+a)=2 tanb=1/2求tan2a的值求sin(a+b)-2sinacosb/2sinasinb+cos(a+b)的值
tanatan2a/(tan2a-tana)+根号3(sin^2a-cos^2)=2sin(2a-派/3) 证明下sin2a怎么来得请说详细
已知tan2a= -2√2 π小于2a小于2π 求(2cos^2 (a/2)-sina-1)/√2sin(a+ π /4)
tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+45`)急用啊
tan2a=-2根号2,2a属于(90`,180`),求[cos^2(a/2)-sina-1]/根号2sin(a+45`)
已知tan(a+4分之π)=4分之3,求tan2a的值已知cos(π+a)=5分之根号5,且a为第三象限,求sin2a和sin(2a+6分之π)
sina=3/5,a∈(0,π/2),求tan2a+根号2cos(a-π/4)
a属于(0,pai/2) tana=1/2 求tan2a和sin(2a+pai/3)的值
求证1、sin l-sin y=2cos(l+y)/2 sin(l-y)/22、cos l+cos y=2cos(l+y)/2 cos(l+y)/23、cos l-cos y=-2sin (l+y)/2 sin (l-y)/24、tanatan2a/(tan2a-tana)+根号3(sin²a-cos²a)=2sin(2a-π/3)对了,还有:是否存在锐角l,y,