2∧x=3 log[4∧(8/3)]=y 则x+2y=
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 03:53:04
2∧x=3log[4∧(8/3)]=y则x+2y=2∧x=3log[4∧(8/3)]=y则x+2y=2∧x=3log[4∧(8/3)]=y则x+2y=x=log2(3)y=lg(8/3)/lg4=lg
2∧x=3 log[4∧(8/3)]=y 则x+2y=
2∧x=3 log[4∧(8/3)]=y 则x+2y=
2∧x=3 log[4∧(8/3)]=y 则x+2y=
x=log2(3)
y=lg(8/3)/lg4
=lg(8/3)/2lg2
=1/2*log2(8/3)
所以x+2y=log2(3)+log2(8/3)
=log2(3×8/3)
=log2(8)
=log2(2³)
=3
已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值
[log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)]^2,则z=?
log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y
若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4(x))]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z=
2∧x=3 log[4∧(8/3)]=y 则x+2y=
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3)
log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4)
数学y=log(3)x+4log(x)3怎么化成y=log(3)x+4/log(3)x?
log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,
(log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0
log(2)(x)log(2)(4x)-3log(2)(x)-12=0
log 3 (4+x+4y)^2=0 联立 log 2 (x+1)^2=1+3log 2 y^2 求
已知log(2)x=5,log(3)y=-2,求log(6)[3x/4y]...(括弧者为底数)
已知log(2){log(3)[log(4)(x)]}=5^0,则x=?
log底数3[log底数4(log底数2y)]=0等于多少?
2 log(3x)= log 4 +log(6-x)怎么求...急
log(3)4*log(4)8*log(8)M =log(2)16 M是多少呃....
函数y=log(1/2)2x+log(1/3)x的单调区间为