-(-10)2nx100x(-10)2n-1=
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-(-10)2nx100x(-10)2n-1=-(-10)2nx100x(-10)2n-1=-(-10)2nx100x(-10)2n-1=原式=-100x4n^2x100-1=80000n^2-1
-(-10)2nx100x(-10)2n-1=
-(-10)2nx100x(-10)2n-1=
-(-10)2nx100x(-10)2n-1=
原式=-100x4n^2x100-1=80000n^2-1
-(-10)2nx100x(-10)2n-1=
n+(n+1)+(n+2)+(n+3)+(n+4)=5n+10这道题怎么解
已知n属于N*,且分段函数f(n)=n-2,n>=10 f[f(n+5)],n
解方程(2n+1)(n+1)n-(2n-21)(n-10)(n-11)=2(2n-9)(n-4)(n-5)
当n为正整数时,定义函数N(n)表示n的最大奇因数.N(3)=3N(10)=5S(n)=N(1)+N(2)+N(3)+...+N(2^n)当n为正整数时,定义函数N(n)表示n的最大奇因数.如N(3)=3N(10)=5.记S(n)=N(1)+N(2)+N(3)+...+N(2^n)则S(4)=---- S(n)=------求
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n是自然数,N=[n+1,n+2,...,3n]是n+1,n+2,...,3n的最小公倍数,如果N可以表示成N=2^10*奇数,n的可能值有几个?
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10^2n+1+10^2n-1/10^2n+1-10^2n-1
(n+2)(10/11)^n+1-(n+1)(10/11)^n 怎么解
lim((2n+1)^5(n+10)^3)/((n^2-2n-3)^4)=32
求极限limn→∞开n次方(1^n+2^n+…+10^n)
(急!)下列哪一组力作用在同一物体上,可以构成合力与分力的关系A.5N,3N,4N,8N,B.10N,8N,2N,1N,C.10N,20N,30N,40N,D.3N,7N,2N,1N,