若cos(π/4+x)=3/5,17π/12＜x ＜7π/4,求(sin2x+2cosx)/1-tanx的值

cos(π/4+x)=3/5,17π/12 cos(π/4+X)=3/5,17π/12 cos(π/4+x)=3/5,17π/12 cos(π/4+x)=3/5,17π/12 cos(π/4+x)=3/5,17/12π cos(π/4+x)=3/5,17π/12 cos(π/4+x)=3/5,17π/12 cos(π/4+x)=3/5,-17π/12 若cos(x+y)=4/5,cos(x-y)=-4/5,且3π/2 若cosx=2/3,x是第四象限角,求sin(x-2π)+sin(-x-3π)cos(x-3π)/cos(π-x)-cos(-π-x)cos(x-4π)的值 三角函数解方程 (cos 3x)^3+ (cos 5x)^3 = 8 (cos 4x)^3 (cos x)^3 若cos(π/4+x)=3/5 17π/12 若cos（π/4+x）=3/5,17/12π 若cos(π/4+x)=3/5,17π/12 若cos(π/4+x)=3/5,17π/12 若cos(π/4+x)=3/5 17π/12 若cos(π/4+x)=3/5 17π/12 若cos（π/4+x)=3/5,17/12π