cos(π/4+x)=3/5,17π/12

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cos(π/4+x)=3/5,17π/12cos(π/4+x)=3/5,17π/12cos(π/4+x)=3/5,17π/12cos(x+π/4)=cosxcosπ/4-sinxsinπ/4=√2/2

cos(π/4+x)=3/5,17π/12
cos(π/4+x)=3/5,17π/12

cos(π/4+x)=3/5,17π/12
cos(x+π/4)
=cosxcosπ/4-sinxsinπ/4
=√2/2*(cosx-sinx)=3/5
cosx-sinx=3√2/5
-sin2x
=cos(2x+π/2)
=2cos²(x+π/4)-1
=-7/25
sin2x=7/25
cosx-sinx=3√2/5
sinx=cosx-3√2/5
平方
sin²x=1-cos²x=cos²x-6√2/5*cosx+18/25
2cos²x-6√2/5*cosx-7/25=0
cosx=7√2/10,cosx=-√2/10
17π/12