x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,
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x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求
x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,
x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,
x^2-xy-2y^2=0是怎么变成(x+y)(x-2y)=0求解,
这个问题很简单 x^2-xy-2y^2=0变为x^2-2xy+xy-2y^2=0变为x(x+y)-2y(x+y)=0变为(x-2y)(x+y)=0
x^2 = x . x
-2y^2 = y . (-2y)
(x+y)(x-2y)
= x . x + x.(-2y) + y.x + y.(-2y)
= x^2-xy-2y^2
x^2-xy-2y^2 = 0
=> (x+y)(x-2y) =0
十字交叉法,一步就到位了。你老师肯定讲过的,这是最基本的因式分解。
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