a1=5,且2a(n+1)=-3an,则an=?
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/20 07:17:54
a1=5,且2a(n+1)=-3an,则an=?a1=5,且2a(n+1)=-3an,则an=?a1=5,且2a(n+1)=-3an,则an=?2a(n+1)=-3an,q=-3/2,an=5*(-3
a1=5,且2a(n+1)=-3an,则an=?
a1=5,且2a(n+1)=-3an,则an=?
a1=5,且2a(n+1)=-3an,则an=?
2a(n+1)=-3an,q=-3/2,an=5*(-3/2)n-1
a1=5,且2a(n+1)=-3an,则an=?
1.a1=3 且 a(n+1)=an+5ana(n+1)2.a1=1 且 a(n+1)=an+2n+13.a1=1 且 a(n+1)=an+1/4n^2-14.a1=1 an=n+1/n*a(n+1)求各题的an
在数列{an}中.a1=3且a(n+1)=an^2,求an
数列{an},a1=3,且a(n+1)=(an)^2,则an的通项公式.
已知数列{an}满足3a(n+1)=2an-4,且a1=1/5,求an
已知数列an满足an*a(n-2)=a(n-1),(n>2且n∈N),a1=2,a2=3,则a2013=?
已知数列{an}满足a(n+1)=an+3n+2,且a1=2,求an=?
在数列an中,a1=1,且满足a(n+1)=3an +2n,求an
已知等差数列{an}满足a(n+1)=an+3n+2,且a1=2,求an.雪地跪拜!
已知数列an满足a(n+1)=an+3n+2,且a1=2,求an
已知数列an,a1=2,且a(n+1)=2an+3n,求an
已知数列{an}满足条件a1=3,且a( n+1)-an=(20)^n+n,求通项公式已知数列{an}满足条件a1=3,且a( n+1)-an=(2)^n+n,求通项公式
已知数列{an}满足a1=1,且an=1/3a(n-1)+(1/3)^n (n≥2,且n∈N+),则数列{an}的通项公式为A.an=3^n/(n+2) B.an=(n+2)/3^n C.an=n+2 D.an=(n+2)3^n
已知数列an,a1=2,a2=3,且a(n+1)=3an-2a(n-1),则an=?
已知数列an中,a1=3/2,an≠0,且an=[3a(n-1)]/[3+2a(n-1)],则a2012=
在数列{an}中,a1=2,a2=5,且a(n+2)-3a(n+1)+2an=0,求an
数列{an}满足a1=1,且an=an-1+3n-2,求an
若数列{an},a1=2/3,且a(n+1)=an+1/【(n+2)(n+1)】,(n∈N+)则通项an=?